find both direction & distance Practice Questions Answers Test with Solutions & More Shortcuts

Answer: (d)

Clearly, C is at the north-west corner

Answer: (a)

Clearly, the route of A is as shown.

Comparing it with the given diagrams, the direction of A will be North-West.

Answer: (c)

The movements of A, B, C and D are shown in figure (i), (ii), (iii) and (iv) respectively.

The final configuration is shown in (v).

Comapring (v) with the diagram, A is in the South-West corner.

Answer: (c)

Clearly, the arrangement is as shown in the adjioning figure.

Rohan's speed = 8 km/hr.

= $8000/{60 x 60}$ m/sec = $20/9$ m/sec.

Rahul's speed = 10 km/hr.

= $10000/{60 x 60}$ m/sec = $25/9$ m/sec.

Since Rohan and Rahul are moving in opposite directions, so they together cover a distance of $({20}/9 + {25}/9)$

i.e., $45/9$ or 5 meters in one second.

To meet at a point, they together have to cover the distance (CD + DA + AB) i.e., 270m.

Now, 5 meters is covered in 1 second.

So, 270 m will be covered in $(1/{5} x 270)$ = 54 seconds.

Now, distance covered by Rohan in 54 seconds = $({20}/9 x 54)$ m = 120 m.

distance covered by Rahul in 54 seconds = $({25}/9 x 54)$ m = 150 m.

Thus, Rohan and Rahul meet for the first time on AD at a point 30 m from A and 60 m from D.

Now, to meet again, Rohan and Rahul will have to complete one full round i.e. together move a distance of 360 m.

5 metres is covered by both together in 1 second.

Thus, 360 m will be covered by both in $({1}/5 x 360)$ = 72 seconds.

Now, distance covered by Rohan in 72 seconds = $({20}/9 x 72)$ = 160 m.

Distance covered by Rahul in 72 seconds = $({25}/9 x 72)$ = 200 m.

Thus, Rohan and Rahul meet on BC at a point 10 m from C and 80 m from B.

Answer: (b)

Clearly, (i), (ii), (iii) and (iv) show the movements of A, B, C and D respectively while the new arrangement so obtained is shown in (v).

So, the configuration changes to CBDA.